Factor 2x^2-19x+24

Problem

2*x2−19*x+24

Solution

1. Identify the coefficients of the quadratic expression a*x2+b*x+c where a=2 b=−19 and c=24

2. Find two numbers that multiply to a⋅c=2⋅24=48 and add to b=−19

3. Determine the pair of numbers, which are −16 and −3 since (−16)⋅(−3)=48 and −16+(−3)=−19

4. Rewrite the middle term −19*x using the two numbers found.

2*x2−16*x−3*x+24

5. Factor by grouping by taking the greatest common factor out of the first two terms and the last two terms.

2*x*(x−8)−3*(x−8)

6. Factor out the common binomial (x−8)

(2*x−3)*(x−8)

Final Answer

2*x2−19*x+24=(2*x−3)*(x−8)

Want more problems? Check here!