Factor 2x^2-11x+12

Problem

2*x2−11*x+12

Solution

1. Identify the coefficients of the quadratic expression a*x2+b*x+c where a=2 b=−11 and c=12

2. Find two numbers that multiply to a⋅c=2⋅12=24 and add to b=−11

3. Determine the pair of numbers, which are −8 and −3 since (−8)⋅(−3)=24 and −8+(−3)=−11

4. Rewrite the middle term −11*x using the two numbers found: 2*x2−8*x−3*x+12

5. Factor by grouping the first two terms and the last two terms: 2*x*(x−4)−3*(x−4)

6. Factor out the common binomial factor (x−4)

Final Answer

2*x2−11*x+12=(2*x−3)*(x−4)

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