Factor 12x^2+17x+6

Problem

12*x2+17*x+6

Solution

1. Identify the coefficients of the quadratic expression a*x2+b*x+c where a=12 b=17 and c=6

2. Calculate the product a*c which is 12⋅6=72

3. Find two numbers that multiply to 72 and add to the middle coefficient b=17 These numbers are 8 and 9

4. Rewrite the middle term 17*x using the two numbers found: 12*x2+8*x+9*x+6

5. Factor by grouping the first two terms and the last two terms: 4*x*(3*x+2)+3*(3*x+2)

6. Factor out the common binomial factor (3*x+2)

Final Answer

12*x2+17*x+6=(4*x+3)*(3*x+2)

Want more problems? Check here!