Factor 10x^2-19x+6

Problem

10*x2−19*x+6

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=10 b=−19 and c=6

2. Calculate the product a*c by multiplying 10 and 6 to get 60

3. Find two numbers that multiply to 60 and add to the middle coefficient b=−19 These numbers are −15 and −4

4. Rewrite the middle term −19*x using the two numbers found: −15*x−4*x

10*x2−15*x−4*x+6

5. Factor by grouping by taking the greatest common factor out of the first two terms and the last two terms.

5*x*(2*x−3)−2*(2*x−3)

6. Factor out the common binomial (2*x−3)

(5*x−2)*(2*x−3)

Final Answer

10*x2−19*x+6=(5*x−2)*(2*x−3)

Want more problems? Check here!