Expand Using the Binomial Theorem (x-6)^2

Problem

(x−6)2

Solution

1. Identify the terms and the exponent for the binomial expansion (a+b)n where a=x b=−6 and n=2

2. Apply the Binomial Theorem formula, which states (a+b)n=(∑_k=0^n)((n/k))*a(n−k)*bk)

3. Write the expansion by substituting the values into the formula for k=0,1,2

(2/0)(x)2*(−6)0+(2/1)(x)1*(−6)1+(2/2)(x)0*(−6)2)))

4. Calculate the coefficients using the combination formula (n/k)=(n!)/(k!(n−k)!))

(2/0)=1)

(2/1)=2)

(2/2)=1)

5. Simplify each term in the expression.

1⋅x2⋅1+2⋅x⋅(−6)+1⋅1⋅36

x2−12*x+36

Final Answer

(x−6)2=x2−12*x+36

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