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Expand Using the Binomial Theorem (x-2)^2

Problem

(x−2)2

Solution

  1. Identify the terms and the exponent for the binomial expansion (a+b)n where a=x b=−2 and n=2

  2. Apply the Binomial Theorem formula, which states (a+b)n=(∑_k=0^n)((n/k))*a(n−k)*bk)

  3. Write the expansion by substituting the values into the formula for k=0,1,2

(x−2)2=(2/0)x2*(−2)0+(2/1)x1*(−2)1+(2/2)x0*(−2)2)))

  1. Calculate the coefficients using the combination formula (n/k)=(n!)/(k!(n−k)!))

(2/0)=1)

(2/1)=2)

(2/2)=1)

  1. Simplify each term in the expression.

(1)*(x2)*(1)+(2)*(x)*(−2)+(1)*(1)*(4)

x2−4*x+4

Final Answer

(x−2)2=x2−4*x+4


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