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Expand Using the Binomial Theorem (2x-5)^2

Problem

(2*x−5)2

Solution

  1. Identify the terms of the binomial (a+b)n where a=2*x b=−5 and n=2

  2. Apply the Binomial Theorem formula, which states (a+b)n=(∑_k=0^n)((n/k))*a(n−k)*bk)

  3. Write the expansion by substituting the values into the formula for k=0,1,2

(2/0)(2*x)2*(−5)0+(2/1)(2*x)1*(−5)1+(2/2)(2*x)0*(−5)2)))

  1. Calculate the coefficients using the combination formula (n/k))

1⋅(2*x)2⋅1+2⋅(2*x)⋅(−5)+1⋅1⋅(−5)2

  1. Simplify each term by squaring the constants and variables.

4*x2−20*x+25

Final Answer

(2*x−5)2=4*x2−20*x+25


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