Evaluate the Summation sum from i=1 to 4 of 4n+1

Problem

(∑_i=1^4)(4*i+1)

Solution

1. Identify the terms of the summation by substituting the index i with each integer from 1 to 4

2. Substitute i=1 to find the first term: 4(1) + 1 = 5$.

3. Substitute i=2 to find the second term: 4(2) + 1 = 9$.

4. Substitute i=3 to find the third term: 4(3) + 1 = 13$.

5. Substitute i=4 to find the fourth term: 4(4) + 1 = 17$.

6. Sum the calculated terms together: 5 + 9 + 13 + 17$.

7. Calculate the final total: 5 + 9 = 14,4 + 13 = 27,a*n*d7 + 17 = 44$.

Final Answer

(∑_i=1^4)(4*i+1)=44

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