Evaluate the Limit
Problem
Solution
Identify the form of the limit by substituting
x=π/2 into the expression.Evaluate the numerator and denominator:
cos(π/2)=0 and1−sin(π/2)=1−1=0 Recognize that the limit results in the indeterminate form
0/0 which allows the use of L'Hôpital's Rule.Apply L'Hôpital's Rule by taking the derivative of the numerator and the derivative of the denominator separately.
Differentiate the numerator:
d(cos(x))/d(x)=−sin(x) Differentiate the denominator:
d(1−sin(x))/d(x)=−cos(x) Simplify the new expression:
(−sin(x))/(−cos(x))=tan(x) Evaluate the limit of the new expression as
x approachesπ/2 from the left:(lim_x→π/2−)(tan(x))=∞ Evaluate the limit of the new expression as
x approachesπ/2 from the right:(lim_x→π/2+)(tan(x))=−∞ Conclude that because the one-sided limits are not equal (and specifically, the function grows without bound), the limit does not exist.
Final Answer
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