Evaluate the Limit
Problem
Solution
Identify the type of limit by substituting
x=5 into the expression.Evaluate the numerator at
x=5 5−5*(5)+6=25−25+6=6 Evaluate the denominator at
x=5 5 - 5 = 0$.Analyze the result of the substitution, which is
6/0 This indicates a vertical asymptote atx=5 Determine the behavior from the left (
x→5 . Asx approaches 5 from the left,x−5 is a very small negative number, so6/small negative→−∞ Determine the behavior from the right (
x→5 . Asx approaches 5 from the right,x−5 is a very small positive number, so6/small positive→∞ Conclude that since the left-hand limit and right-hand limit do not match and grow without bound, the limit does not exist.
Final Answer
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