Evaluate square root of 68

Problem

√(,68)

Solution

1. Identify the number under the radical and look for its perfect square factors.

2. Factor the number 68 into a product of a perfect square and another integer.

√(,68)=√(,4⋅17)

3. Apply the product property of radicals, which states that √(,a⋅b)=√(,a)⋅√(,b)

√(,4⋅17)=√(,4)⋅√(,17)

4. Simplify the square root of the perfect square factor.

√(,4)⋅√(,17)=2√(,17)

Final Answer

√(,68)=2√(,17)

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