Evaluate square root of 242

Problem

√(,242)

Solution

1. Identify the number inside the square root and look for perfect square factors.

2. Factor the number 242 into a product of a perfect square and another integer.

242=121⋅2

3. Apply the product property of square roots, which states √(,a⋅b)=√(,a)⋅√(,b)

√(,242)=√(,121⋅2)

√(,242)=√(,121)⋅√(,2)

4. Simplify the square root of the perfect square 121

√(,121)=11

5. Combine the results to find the simplified radical form.

√(,242)=11√(,2)

Final Answer

√(,242)=11√(,2)

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