Evaluate square root of (2-3)^2+(-3-6)^2

Problem

√(,(2−3)2+(−3−6)2)

Solution

1. Simplify the expressions inside the parentheses.

2−3=−1

−3−6=−9

2. Square the resulting values.

(−1)2=1

(−9)2=81

3. Add the squared values together inside the square root.

1+81=82

4. Evaluate the final square root expression. Since 82 has no perfect square factors other than 1, the expression is in simplest radical form.

√(,82)

Final Answer

√(,(2−3)2+(−3−6)2)=√(,82)

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