Evaluate 4 square root of 295

Problem

4√(,295)

Solution

1. Identify the number under the radical to see if it has any perfect square factors.

2. Find the prime factorization of 295

3. Divide 295 by the smallest prime factor, which is 5

295=5×59

4. Check if 59 is a prime number. Since 59 is not divisible by 2, 3, 5,o*r$, it is prime.

5. Conclude that since 295 has no repeating prime factors, it has no perfect square factors other than 1

6. Determine that the radical expression cannot be simplified further into a simpler radical form.

Final Answer

4√(,295)=4√(,295)

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