Editorial - Matwa - EK

EK

Problem 1

3 kemungkinan.

P=3/(2⋅2)=3/4

(C)

Problem 2

Total kemungkinan: 10!/(3!7!)=120

1 kelereng biru 2 kelereng merah: 3⋅7!/(2!5!)=63

2 kelereng biru 1 kelereng merah: 3!/(2!1!)⋅7=21

3 kelereng biru 0 kelereng merah: 1

P=(63+21+1)/120=17/24

(E)

Problem 3

1+5=6

2+4=6

3+3=6

4+2=6

5+1=6

1+6=7

2+5=7

3+4=7

4+3=7

5+2=7

6+1=7

2+6=8

3+5=8

4+4=8

5+3=8

6+2=8

P=16/(6⋅6)=4/9

(C)

Problem 4

(P_merah)=5/10=1/2

(P_putih)=3/10

P=1/2+3/10=4/5=0.8

(D)

Problem 5

(C)

Problem 6

P=2/6⋅2/6=1/9

(B)

Problem 7

13/52⋅13/52=1/16

(B)

Problem 8

P=8/21⋅7/20=2/15

(B)

Problem 9

P=40/500=2/25

Problem 10

P=3/7⋅7/9=1/3=21/63=1/3

(B)