Factor 5x^2-14x-3

Problem

5*x2−14*x−3

Solution

1. Identify the coefficients of the quadratic expression a*x2+b*x+c where a=5 b=−14 and c=−3

2. Find two numbers that multiply to a⋅c=5⋅(−3)=−15 and add to b=−14

3. Determine the pair of numbers, which are −15 and 1 since (−15)⋅1=−15 and −15+1=−14

4. Rewrite the middle term −14*x using these two numbers: 5*x2−15*x+x−3

5. Factor by grouping the first two terms and the last two terms: 5*x*(x−3)+1*(x−3)

6. Factor out the common binomial (x−3) to obtain the final factored form.

Final Answer

5*x2−14*x−3=(5*x+1)*(x−3)

Want more problems? Check here!