Calculus IV / Midterm I
Credit: Emma K's notes, MT-1 top sheet
TODO: scribe lecture
CLP Cutoff:
1. A review of important properties
a⋅(b+c)=a⋅b+a⋅c a⋅a=‖a‖2 (c*a)⋅b=c*(a⋅b) a⋅b=‖a‖*‖b‖*cos(θ) ‖a⨯b‖=‖a‖*‖b‖*sin(θ) a⨯b=-(b⨯a) (c*a)⨯b=c*(a⨯b)=a⨯(c*b) a⋅(b⨯c)=(a⨯b)⋅c a⨯(b⨯c)=(c⋅a)*b-(b⋅a)*c a⨯(b+c)=a⨯b+a⨯c
2. Vector Valued Functions
A vector valued function is a function that takes
1 or more variables as an input and outputs a vector in real space (real space isℝ2 orℝ3 for example).Vector valued functions have the form
r=<x,y,z>=x*i+y*j+z*k We often use parametric representations for the componenets of
r using1 or more parameters (i.e.r=<x(t),y*(t),z(t)> ).If
r is a vector-valued function pointing to the position of an object moving through space (we are modelling this object as a flying dot), then it's velocity isv=d(r)/d(t)=r=<x(t),y(t),z(t)> , and its acceleration isa=(d^2)(r)/d(t2)=d(v)/d(t) .The velocity vector is tangent to the curve at the point
r(t) . We can find a vector of length1 that points in the direction ofv by normalizing it:T=v/‖v‖ . This is called the unit tangent vector.
3. Parametrization of a circle
A circle in the plane can be parametrically represented by the vector-valued function
r=<R*cos(θ)+a,R*sin(θ)+b> , whereR is the radius of the circle, and(a,b) is the center of the circle.The speed of the moving object is given by
v=‖v‖=θ*R, whereθ (also sometimesω ) is the angular speed (The rate of change of angle subtended by the arc traced by the moving dot w.r.t time).The acceleration of the moving dot is given by
a=d(v)/d(t)*T+R*θ2*N=d(v)/d(t)*T+(v2)/R*N, whereN=<-cos(θ),-sin(θ)> , the principal unit normal vector, points towards the circle (more on that later).
4. Derivatives and integrals of vector-valued functions
The fundamental theorem of caluclus also applies to vectors
(∫_(t_0)^(t_1))(d(r)/d(t)*d(t))=r((t_1))-r((t_0)), Properties of derivartives of vector-valued functions
Let
u=u(t),v=v(t) be inℝn andLet
φ=φ(t),ƒ=ƒ(x,y,z) be scalar functions. Thend()/d(t)*[φ(t)*u(t)]=d(φ)/d(t)*u+φd(u)/d(t) d()/d(t)*[u(t)⋅v(t)]=d(u)/d(t)⋅v+u⋅d(v)/d(t) d()/d(t)*[u(t)⨯v(t)]=d(u)/d(t)⨯v+u⨯d(v)/d(t) d()/d(t)*[ƒ(u(t))]=∇ƒ(u(t))d(u)/d(t) d()/d(t)*[u(φ(t))]=u(φ(t))*φ(t) d()/d(t)*[‖u(t)‖]=(u(t)⋅d(u)/d(t))/‖u(t)‖
5. Rate of change of distance and speed
The rate of change of speed of an object is given by
d()/d(t)*[‖r‖]=(r⋅v)/‖r‖ If this quantity is positive, the object is moving away from the origin. If it is negative, then the object is moving towards the origin.
The rate of change of speed is
d()/d(t)*[v(t)]=(v⋅a)/‖v‖ If this quantity is positive, then the speed and acceleration are at an acute angle. If it is negative, they are at ana obtuse angle. If it is
0 , thenv⟂a for allt
6. Arc-length
In general, the arc-length of a curve generated by
r(t) iss=(∫_0^t)(d(s))=(∫_0^t)(‖(r^′)(t)‖)*d(t)=(∫_0^t)(‖v(t)‖)*d(t) If we reparametrize our function in terms of polar coordinates, where
x=r*cos(t),y=r*sin(t),r=r(t) , andθ=θ(t) , thend(s) becomesd(s)=√(,(d(r))2+r2*(d(θ))2) If you solve for arclength and then solve for
t as a function ofs , then you can reparametrize a functionr(t) asr(t(s)) . This function will have the same speed for allt .
7. The independence of curve geometry to parametrization
Therte are an infinite number of parametrizations for a given curve in space
The general form of the eqation of a line segment is
r=(r_0)+t*v,a<t<b where(r_0) is a vector pointing to a point on the line andv is a vector parallel to the line. This mimics the formy=m*x+b in 2D.It is helpful to think of this through vector addition using the tip-to-tail method.
(r_0) points to the line, andr points to the sum of this vector and scalar multiuples (more specificallyt multiples) ofv .Thinking about this definition, you could replace
v with any scalar multiple,c*v , since it would be parallel and get the same line. Likewise, you could replacet with any function oft , sayƒ(t) , and you would get the same line. This is provided that you adjust the bounds ont so that the line segment starts and ends in the same place.In general, any curve generated by
r(t) will also be generated byr(u(t)) have the same physical properties.
8. The binormal and principal unit vectors
The pincipal unit normal vector,
N , is the vector that is perpendicular to trhe unit tangent vector,T , and points inward relative to the curve.N is calculated asN=(T^′)/‖(T^′)‖=((v⨯a)⨯v)/‖(v⨯a)⨯v‖ The binormal vector,
B , is the vector that is orthogonal to bothN andB .B is calculated asB=T⨯N=(v⨯a)/‖v⨯a‖ B,N, andT can be thought of as an alternative basis that moves with the object along the curve. The plane is spanned byT andN and that is orthogonal toB is called the osculating plane (from the latin word for to kiss).T ,N , andB have the property thatT=N⨯B N=B⨯T B=T⨯N
9. Torsion and Curvature
Curvature,
κ , measures how much a curve "curves" it is calculated asκ=‖(r^′)⨯(r^″)‖/(‖(r^′)‖3)=‖(T^′)(s)‖=‖(r^″)(s)‖=‖(T^′)(t)‖/‖(r^′)(t)‖=(a⋅N)/(‖v(t)‖2) The first equation is usually used the most.When a curve is constrained to the plane
z=0 , that is the 𝓍𝓎-plane, the formula for curvature reduces toκ=|(x^′)*(y^″)-(y^′)*(x^″)|/([((x^′))2+((y^′))2](3/2)) ifx andy are both functions oft orκ=|(y^″)|/([1+((y^′))2](3/2)) if you have an explicit function fory in terms ofx .The osculating circle at
t is the cricle that best fits the curver(t) att .The radius of the osculating circle,
ρ , is called the radius of curvature and is calculated asρ=1/κ .The torsion (not to be confused with torque) of a curve,
τ , is trhe "out of plane twist." If you imagine a helix in space, the more coiled the helix is , the greather the torision will be. It also describes how much the osculating plane will "wobble."Torsion is calculated as
τ=((v⨯a)⋅d(a)/d(t))/(‖v⨯a‖2) If a curve is contained in a plane (that is, its points are co-planar), then the torsion
τ=0.
10. Normal and tangential components of acceleration
At this point, we have developed enough tools to find several forms of the equation
a=(a_T)*T+(a_N)*N The tangent component of acceleration can be written as
(a_T)=a⋅T=((r^′)⋅(r^″))/‖(r^′)‖=d(v)/d(t)=(d^2)(s)/d(t2) The normal (or sometimes centripetal in physics) component of acceleration can be written as
(a_N)=a⋅N=v2*κ=‖v⨯a‖/‖v‖=√(,‖a‖2-(a_T)2)=κ*(d(s)/d(t))2
11. MGM Problems
MGM problems arise when we are given some properties of a curve, but not the vector-valued parametric function generating the curve itself.
The way of solving these problems consists of three steps:
Create "fake" parametrization generating the same geometric curve
Find intrinsic geometric information (one of more of
κ,τ,T,N,B,ρ ) using this parametrizationCombine this information with the information provided to find the intended parametrization for the function
It is important to take note of the direction of
t . If, say,x is decreasing, it may be advantageous to usex=-t for a particular curve.
12. Frenet-Serret formulas
These are three formulas that relate
T,N , andB to each-other. They are as followsd(T)/d(t)=v*κ*N d(B)/d(t)=-v*τ*N d(N)/d(t)=v*τ*B-v*κ*T
13. The fundamental theorem of space curves
If
(r_1)(t) and(r_2)(t) are two smooth parametric curves that are defined on the same interval[a,b] , have the same speedv(t) , curvatureκ(t) , and torsionτ(t) , then(r_1)(t) and(r_2)(t) are geometrically congruent. That is, their curves can be moved so that they line up with one another perfectly.
14. Angular momentum
Anuglar momentum is defined as
H=r⨯(m*v) wherem is the mass of the object traced byr We define a useful quantity
h=H/m=r⨯v If there is no outside torque acting on the system, that is, all forces are parallel to
r , then angular momentum is conserved, andh is constant.If this is the case, than all motion will be confined to a plane. This will be used as part of the setup for Kepler's laws.
15. Polar coordinates
The polar coordinate system defines a curve using the distance from the origin as a function of the angle travelled counter-clockwise from the positive x-axis,
r(θ) .Recall that to go from rectangular coordinates to polar, use
x=r*cos(θ),y=sin(θ) .In vector form, rather than using
i andj as an orthnormal basis, we user=r/‖r‖=<cos(θ),sin(θ)> andθ=<-sin(θ),cos(θ)> An easy way of remembering this is to just think of the unit circle. You want
r to point to one unit in the direction of the terminal array (arm), so just defined it as you would the coordinates of the unit circle. Notice that the components ofθ are the derivative of the components ofr . You can actually define these areT and-N for the typical parametric representation of the unit circle.Let
θ=θ(t) . It is important to know these derivative properties and identites for objects moving in the plane:d(r)/d(t)=θ*θ d(θ)/d(t)=-θ*r r⨯θ=k v=r*r+r*θ*θ v=‖v‖=√(,r2+r2*θ2) (r-r*θ2)*r+(r*θ+2*r*θ)*θ If momentum is conserved then,
h=r2*θ*k
16. Kepler's Laws
Kepler's laws are mathematical relationships that descrive trhe orbit of the planets around the sun. They can be proved usding Newtonian mechanics and rewritten as formulas. They are as follows:
The planets orbit the sun in elliptical paths, with the sun at one of the foci
For each planet, in equal time intervals, the areas swept out by the cord from the orbiting body to the sun are equal (equal areas in equal time intervals)
T2∝a3 , whereT is the orbital period anda is the semi-major axis of the ellipse.
The setting for Kepler's laws is that the planets are modelled as moving points decribed by
r and with massm , momentum is conserved so that all of the motion of the planets are restricted to a plane (z=0 in math), and the force experienced by the planets is given by(F_g)=-G(M*m)/(r2)*r=m*a In this equationG is the gravitational constant, empircally measured,M is the mass of the sun,m is the mass of the planet,r is the distance between the planet and the sun, anda is the acceleration of the planet. We fix the focus with the sun on it at the origin to simplify calculations.Kepler II: If
A(a,b) is the area swept out by the planet froma tob , thenA(a,b)=(∫_θ(a)^θ(b))(1/2*r2*d(θ))=1/2*(∫_a^b)(h*d(t))=h/2*(b-a) This is a mathematical demonstration thatA depends only on the length of the time interval.Kepler I: the polar function
r(θ) describing the distance from the sun to the planet is given byr=l/(1+ε*cos(θ)) , wherel=(h2)/(G*M) This is the equation of an ellipse in polar.Note that the horizontal leftward shoft of the ellipse if given by
c=(ε*l)/(1-ε2) The semi-major axis is
a=l/(1-ε2) and the semi-minor axis is
b=l/√(,1-ε2) The variable
ε is the eccentricity of the ellipse and describes the ratio between its semi-major and semi-minor axes. We have thatb/a=√(,1-ε2) and0<ε<1
Kepler III: If
T represents the period of the planet's orbit (how long its year is), thenT2=(4*π2)/(G*M)*a3 This shows thatT2∝a3 and their ratio is equal for all planets.