Factor n^2+4n-12

Problem

n2+4*n−12

Solution

1. Identify the coefficients of the quadratic expression in the form a*n2+b*n+c where a=1 b=4 and c=−12

2. Find two integers that multiply to give the product a*c=−12 and add to give the sum b=4

3. Determine the pair of numbers by testing factors of −12 the pair 6 and −2 works because 6×−2=−12 and 6 + (-2) = 4$.

4. Write the expression in factored form (n+p)*(n+q) using the identified integers.

Final Answer

n2+4*n−12=(n+6)*(n−2)

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