Solve for x sec((5x)/4)=2

Problem

sec⁡5⁢x4=2 the secant of 5 x over 4 equals 2

Solution

  1. Rewrite the equation in terms of the cosine function using the reciprocal identity sec⁡θ=1cos⁡θ secant theta equals 1 over cosine theta

cos⁡5⁢x4=12 the cosine of 5 x over 4 equals one half

  1. Identify the general solutions for the cosine equation cos⁡θ=12 cosine theta equals one half on the unit circle.

5⁢x4=π3+2⁢π⁢n 5 x over 4 equals pi over 3 plus 2 pi n

5⁢x4=−π3+2⁢π⁢n 5 x over 4 equals negative pi over 3 plus 2 pi n

  1. Isolate x x in the first general solution by multiplying both sides by 45 four fifths

x=45⁢(π3+2⁢π⁢n) x equals four fifths times open paren pi over 3 plus 2 pi n close paren

x=4⁢π15+8⁢π⁢n5 x equals 4 pi over 15 plus 8 pi n over 5

  1. Isolate x x in the second general solution by multiplying both sides by 45 four fifths

x=45⁢(−π3+2⁢π⁢n) x equals four fifths times open paren negative pi over 3 plus 2 pi n close paren

x=−4⁢π15+8⁢π⁢n5 x equals negative 4 pi over 15 plus 8 pi n over 5

Final Answer

sec⁡5⁢x4=2⇒x=±4⁢π15+8⁢π⁢n5 the secant of 5 x over 4 equals 2 right double arrow x equals plus or minus 4 pi over 15 plus 8 pi n over 5


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