Find the Exact Value sin(-150 degrees )
Problem
Solution
Use the odd function property of the sine function, which states that
sin(−θ)=−sin(θ)
Find the reference angle for
150^∘ Since150^∘ is in the second quadrant, the reference angle is180^∘−150^∘=30^∘
Determine the sign of the sine function in the second quadrant. Since sine is positive in the second quadrant,
sin(150^∘)=sin(30^∘)
Substitute the known value for
sin(30^∘) which is1/2
Combine the results to find the final value.
Final Answer
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