Find the Prime Factorization 105

Problem

105

Solution

1. Check for divisibility by the smallest prime number, 2 Since 105 is odd, it is not divisible by 2

2. Check for divisibility by the next prime number, 3 The sum of the digits is 1 + 0 + 5 = 6.S*i*n*c*ei*s(d(i))*v*i*s(i)*b*l*e*b*y,05i*s(d(i))*v*i*s(i)*b*l*e*b*y$.

3. Divide 105 by 3

105÷3=35

4. Check for divisibility of 35 by 3 The sum of the digits is 3 + 5 = 8,w*h*i*c*h*i*s(n)*o*t*d(i)*v*i*s(i)*b*l*e*b*y$.

5. Check for divisibility by the next prime number, 5 Since 35 ends in 5 it is divisible by 5

6. Divide 35 by 5

35÷5=7

7. Identify that 7 is a prime number. The process is complete.

Final Answer

105=3⋅5⋅7

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