Factor y^2-8y+16

Problem

y^2−8*y+16

Solution

1. Identify the structure of the quadratic expression, which is in the form a*y^2+b*y+c where a=1 b=−8 and c=16

2. Recognize that the expression is a perfect square trinomial because the first term is y^2 the last term is 4^2 and the middle term is −2*(y)*(4)

3. Apply the formula for a perfect square trinomial, which states a^2−2*a*b+b^2=(a−b)^2

4. Substitute a=y and b=4 into the binomial square form.

Final Answer

y^2−8*y+16=(y−4)^2

Want more problems? Check here!