Graph x^2+y^2=36
Problem
Solution
Identify the type of equation. The equation
x^2+y^2=36 is in the standard form of a circle centered at the origin, which isx^2+y^2=r^2 Determine the center of the circle. Since there are no horizontal or vertical shifts (no
h ork values subtracted fromx ory , the center is at(0,0) Calculate the radius. The constant on the right side represents
r^2
Plot the key points. Starting from the center
(0,0) move6 units in each cardinal direction to find the intercepts:(6,0) (−6,0) (0,6) and(0,−6) Sketch the graph. Draw a smooth curve connecting these four points to form a circle with a radius of
6
Final Answer
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