Factor x^2-14x+49

Problem

x^2−14*x+49

Solution

1. Identify the structure of the quadratic expression, which is in the form a*x^2+b*x+c where a=1 b=−14 and c=49

2. Recognize that the expression is a perfect square trinomial because the first term is x^2 the last term is 7^2 and the middle term is −2*(x)*(7)

3. Apply the formula for a perfect square trinomial, a^2−2*a*b+b^2=(a−b)^2

4. Substitute x for a and 7 for b into the binomial square form.

Final Answer

x^2−14*x+49=(x−7)^2

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