Evaluate cube root of 27

Problem

√(3,27)

Solution

1. Identify the number whose cube is equal to the radicand, 27.

2. Factor the number 27 into its prime factors to see if it is a perfect cube.

27=3⋅3⋅3

3. Rewrite the expression using the base and the exponent.

27=3

4. Apply the property of radicals where √(n,xn)=x for any positive integer n

√(3,3)=3

Final Answer

√(3,27)=3

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