Graph x=y^2
Problem
Solution
Identify the type of equation. This is a horizontal parabola because
x is a function ofy^2 Determine the vertex. Since there are no horizontal or vertical shifts, the vertex is at the origin
(0,0) Determine the orientation. Because the coefficient of
y^2 is positive, the parabola opens to the right.Calculate sample points to define the shape. If
y=1 thenx=1^2=1 Ify=−1 thenx=(−1)^2=1 Ify=2 thenx=2^2=4 Ify=−2 thenx=(−2)^2=4 Plot the points
(0,0) (1,1) (1,−1) (4,2) and(4,−2) and connect them with a smooth curve opening to the right.
Final Answer
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