Graph x=y^2
Problem
Solution
Identify the type of equation. This is a horizontal parabola because
x is a function ofy2 Determine the vertex. Since there are no horizontal or vertical shifts, the vertex is at the origin
(0,0) Determine the orientation. Because the coefficient of
y2 is positive, the parabola opens to the right.Calculate sample points to define the shape. If
y=1 thenx=1=1 Ify=−1 thenx=(−1)2=1 Ify=2 thenx=2=4 Ify=−2 thenx=(−2)2=4 Plot the points
(0,0) (1,1) (1,−1) (4,2) and(4,−2) and connect them with a smooth curve opening to the right.
Final Answer
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