Editorial - Fisika - UC TKA

Problem 1

Benda I 6.76 centimeters

Benda II 1.042 centimeters

Benda III 5.7 centimeters

First statement is true.

Second statement true.

Third statement is false.

Fourth statement is true, the total is 13.5 centimeters

Fifth statement is false, it's 1.06 centimetersturns into 1.1 centimeters

Problem 2

3.41 times 26 equals 88.66 equals 89 centimeters

Problem 3

4 times t equals 60 minus 2 t squared over 2

4 t equals 60 minus t squared

t squared plus 4 t minus 60 equals 0

open paren t plus 10 close paren times open paren t minus 6 close paren

t equals the set negative 10 comma positive 6

Taking positive, t equals 6 seconds

Distance s equals 6 times 4 equals 24

Problem 4

Subproblem 4.1

A accelerates faster than B.

Clearly false, as A doesn't accelerate.

Subproblem 4.2

After 10 seconds, the distance between the 2 cars is 400 meters

Let's check that.

s sub 1 equals 80 times 10 equals 800 meters

s sub 2 equals 4 times the fraction with numerator 10 squared and denominator 2 equals 200 meters

The statement is false.

Subproblem 4.3

The 2 cars intersect after 40 seconds

s sub 1 equals 80 times 40 equals 3200 meters

s sub 2 equals 4 times the fraction with numerator 40 squared and denominator 2 equals 3200 meters

The statement is true.

Subproblem 4.4

The 2 cars intersect after 3200 meters

Clearly true, from the previous subproblem.

Subproblem 4.5

The second car has an acceleration of 4 meters divided by seconds to the second power

True.

Problem 5

Okay, so first let's find how long it takes for Charlie to drop from 45 meters.

45 equals 10 t squared over 2

t squared equals 45 times two tenths equals 9

t equals 3 seconds

That's 3 seconds needed to go through 60 meters

60 equals 3 v

v equals 20 meters divided by seconds

That's the target speed.

Let v sub 0 be the starting velocity.

20 squared equals v sub 0 squared plus 2 times 2.5 times 75

v sub 0 equals 5 meters divided by seconds to the second power

Problem 6

40 meters in 1 second, that's the horizontal speed.

v sub x equals 40 meters divided by seconds

v sub y 0 equals?

35 equals v sub y 0 times 1 minus 10 times the fraction with numerator 1 squared and denominator 2

v sub y 0 equals 40 meters divided by seconds

That means we know the tangent values.

tangent alpha equals 1

Let's solve the problem now.

v sub 0 squared sine squared alpha over 2 g colon v sub 0 squared 2 sine alpha cosine alpha over g

sine alpha over 2 colon 2 cosine alpha

the fraction with numerator the square root of 2 and denominator 2 colon 4 times the fraction with numerator the square root of 2 and denominator 2

1 colon 4

Yippee!

Problem 7

N equals 600 times 10 equals 6000 Newtons

Let's find the friction force.

F sub f with hook equals 6000 mu equals 600 a

a equals 10 mu

The car experiences a slowdown of 20 meters divided by seconds in a matter of 60 seconds, so that's one third meters per second squared.

one third equals 10 mu

mu equals 1 over 30

Problem 8

Only acceleration affects perceived weight.

Statements 1, 4, and 5 are true.

Problem 9

0.4 times 6 minus 0.6 times 8 equals 1 v

v equals 2.4 minus 4.8 equals negative 2.4 meters divided by seconds

Problem 10

I equals 0.5 times 10 equals 5

5 equals 20 times triangle of t

triangle of t equals 5 over 20 equals 0.25 seconds

Problem 11

Momen gaya maksimal terjadi ketika komponen gaya yang tegak lurus terhadap lengan gaya berada pada nilai tertinggi, dan gaya tersebut diterapkan pada lengan gaya terpanjang yang mungkin.

Problem 12

I equals 0.8 times 16 times the fraction with numerator 10 to the negative 4 power and denominator 2 equals 1.28 times the fraction with numerator 10 to the negative 5 power and denominator 2 equals 6.4 times 10 to the negative 4 power

omega equals 2 pi times 1200 over 60 equals 40 pi

alpha equals 40 pi over 30 equals four thirds pi

tau equals 6.4 times 10 to the negative 4 power times four thirds pi equals 8.5 pi times 10 to the negative 4 power

Problem 13

50 over 4 equals F over 1600

F equals 20000 Newtons

Problem 14

rho times V equals V times 10 cubed times four fifths

rho equals 800 kilograms divided by cubic meters

Problem 15

200 equals 80 over 100 times lamda

lamda equals 250 Hz

Problem 16