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| (7*π)/6+2*k*π,(11*π)/6+2*k*π | |
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| 2,Period=2*π,Phase Shift=0 | |
| 1,Period=2*π,Phase Shift=0 | |
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(sin(x)+cos(x))2=1+sin(2*x) | | |
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| 4,Period=2*π,Phase Shift=0 | |
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| 2,Period=2*π,Phase Shift=0 | |
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sec(x)−cos(x)=sin(x)*tan(x) | | |
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tan(x)+cot(x)=sec(x)*csc(x) | | |
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cos(θ)* given the point *(21,28) | | |
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| 1,Period=π/2,Phase Shift=0 | |
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| 5*sin(2*x)* has amplitude *5* and period *π | |
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| 3,Period=2*π,Phase Shift=0 | |
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√(,(1−sin(θ))*(1+sin(θ))) | | Simplify square root (1-sin(theta))(1+sin(theta)) |
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| (5*π)/6+2*n*π,(7*π)/6+2*n*π | |
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Solve the triangle with *a=2,b=2,c=2 | | |
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| (2*π)/3+2*n*π,(4*π)/3+2*n*π | |
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| (4*π)/3* is in Quadrant III | |
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| 2,Period=2*π,Phase Shift=0 | |
| 3,Period=2*π,Phase Shift=0 | |
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sec(x)−sec(x)*sin2(x)=cos(x) | | |
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cos(x)/(1−sin(x))=sec(x)+tan(x) | | |
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| 1,Period=(2*π)/5,Phase Shift=0 | |
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| √(,2)*(cos(π/4)+i*sin(π/4)) | |
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| 1,Period=2*π,Phase Shift=0 | |
cos(x)/(1+sin(x))+(1+sin(x))/cos(x)=2*sec(x) | | |
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| (√(,10+2√(,5))+√(,3)−√(,15))/8 | |
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| (5*π)/12+π*k,(7*π)/12+π*k | |
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| 3,Period=2*π,Phase Shift=0 | |
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| 3,Period=π/2,Phase Shift=2*π | |
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cos(θ)* given the point *(0,−2) | | |
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| 3√(,2)*(cos(π/4)+i*sin(π/4)) | |
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| 4,Period=2*π,Phase Shift=0 | |
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sin(θ)=−1/2,θ∈Quadrant III | | |
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| π/3+2*n*π,(5*π)/3+2*n*π,π+2*n*π | |
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100/(1+25*e(−0.095*t))=70 | | |
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sin(x)/(1+cos(x))+(1+cos(x))/sin(x)=2*csc(x) | | |
csc(x)−sin(x)=cot(x)*cos(x) | | |
tan(x)+cot(x)=1/(sin(x)*cos(x)) | | |
csc(x)−sin(x)=cos(x)*cot(x) | | |
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| 1,Period=(2*π)/3,Phase Shift=0 | |
| 1,Period=(2*π)/3,Phase Shift=0 | |
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| 1,Period=π/2,Phase Shift=0 | |
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| 3√(,2)*(cos((7*π)/4)+i*sin((7*π)/4)) | |
sin(θ)* given *(x,y)=(−1/2,√(,3)/2) | | |
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sin(θ)* given *(x,y)=(−√(,3)/2,−1/2) | | |
sin(θ)* given *(x,y)=(−4,3) | | |
| 5√(,2)*(cos((7*π)/4)+i*sin((7*π)/4)) | |
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| 3,Period=2*π,Phase Shift=0 | |
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sec(x)−tan(x)*sin(x)=1/sec(x) | | |
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tan(2*x)=2/(cot(x)−tan(x)) | | |
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| (1+√(,5)+√(,30−6√(,5)))/8 | |
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| (3−4*cos(2*x)+cos(4*x))/8 | |
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sin(2*x)*cos(x)+cos(2*x)*sin(x)=0 | | |
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tan(a)+cot(a)=sec(a)*csc(a) | | |
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sin(x)/(1−cos(x))=csc(x)+cot(x) | | |
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| 3*(cos((3*π)/2)+i*sin((3*π)/2)) | |
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sin(θ)* given the point *(−2,−9) | | |
sin(θ)* given *(x,y)=(−3,−4) | | |
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| 2*(cos((3*π)/2)+i*sin((3*π)/2)) | |
| 2√(,2)*(cos(π/4)+i*sin(π/4)) | |
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| 3,Period=π/2,Phase Shift=0 | |
| 1,Period=π/3,Phase Shift=0 | |
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| 1,Period=2*π,Phase Shift=−π | |
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tan2(x)−sin2(x)=tan2(x)*sin2(x) | | |
sin(x)*(cot(x)+tan(x))=sec(x) | | |
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| (√(,5)−1+√(,30+6√(,5)))/8 | |
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| 2*n*π,(2*π)/3+2*n*π,(4*π)/3+2*n*π | |
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tan(θ)=√(,3),θ∈Quadrant I | | |
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cos(θ)+cos(θ+2*π)+cos(θ+4*π) | | |
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| sin(a)*cos(b)+cos(a)*sin(b) | |
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sin(θ)=12/13,θ∈Quadrant I | | |
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| (2*π)/3+2*n*π,(4*π)/3+2*n*π | |
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| π/4+(n*π)/2* for any integer *n | |
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1/(1+sin(x))−1/(1−sin(x)) | | |
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| (cos(θ)−sin(θ))/(sin(θ)*cos(θ)) | |
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| (√(,3)√(,10+2√(,5))−(√(,5)−1))/8 | |
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tan(x)+cos(x)/(1+sin(x))=1/cos(x) | | |
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cot(x)+tan(x)=sec(x)*csc(x) | | |
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| 3,Period=2*π,Phase Shift=0 | |
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| 2√(,2)*(cos((7*π)/4)+i*sin((7*π)/4)) | |
| 5*(cos((3*π)/2)+i*sin((3*π)/2)) | |
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cos(θ)* given the point *(3,4) | | |
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sin(θ)* given the point *(−5,12) | | |
sin(θ)* given *(x,y)=(3,−4) | | |
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| 1,Period=(2*π)/5,Phase Shift=0 | |
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(1+cos(x))/sin(x)+sin(x)/(1+cos(x))=2*csc(x) | | |
(1+sin(x))/cos(x)+cos(x)/(1+sin(x))=2*sec(x) | | |
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sin(x)/(1−cos(x))+sin(x)/(1+cos(x))=2*csc(x) | | |
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tan(x)*sin(x)+cos(x)=sec(x) | | |
sec(x)−sin(x)*tan(x)=cos(x) | | |
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| 3/8−1/2*cos(2*x)+1/8*cos(4*x) | |
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| (2√(,5+√(,5))−√(,10)+√(,2))/8 | |
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√(,((1−cos(θ))*(1+cos(θ)))/cos2(θ)) | | Simplify square root of (1-cos(theta))(1+cos(theta))/(cos^2(theta)) |
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| (2*π)/3+2*k*π,(4*π)/3+2*k*π | |
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ln(x−6)+ln(x−5)=ln(16−2*x) | | |
| n*π,(2*π)/3+2*n*π,(4*π)/3+2*n*π | |
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cos(θ)=−3/5,θ∈Quadrant III | | |
cos(x)=−5/13, Quadrant II | | |
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(sin(θ)−cos(θ))−(sin(θ)+cos(θ))2 | sin(θ)−cos(θ)−2*sin(θ)*cos(θ)−1 | |
sin(θ)+sin(θ+2*π)+sin(θ+4*π) | | |
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(sin3(θ)+cos3(θ))/(sin(θ)+cos(θ)) | | |
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| sin(x)*cos(y)+cos(x)*sin(y) | |
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x*(tan(44)−tan(28))=470*tan(28) | (470*tan(28))/(tan(44)−tan(28)) | |
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| 0⇒x=π*(2*n+1),x=±π/3+2*n*π | |
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sin(x)/cos(x)+cos(x)/(1+sin(x)) | | |
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| 4*sin(x)*cos3(x)−4*sin3(x)*cos(x) | |
| 3/8+1/2*cos(2*x)+1/8*cos(4*x) | |
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csc(x)−csc(x)*cos2(x)=sin(x) | | |
| cos(x)* is not an identity | |
sec(x)/cos(x)−tan(x)/cot(x)=1 | | |
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cos(x)/(1+sin(x))=sec(x)−tan(x) | | |
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| 1,Period=2*π,Phase Shift=π/2 | |
| 5,Period=2*π,Phase Shift=0 | |
| 7,Period=2*π,Phase Shift=0 | |
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Find *sin(θ)* given the point *(−12,5) | | |
Find the Tangent Given the Point *(3,−4) | | |
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| The angle −(2*π)/3* is in Quadrant III | |
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cos(θ)* given *(x,y)=(9,40) | | |
sin(θ)* given *(x,y)=(12,5) | | |
sin(θ)* given *(x,y)=(3,4) | | |
cos(θ)* given the point *(−12,5) | | |
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| 2*(cos((11*π)/6)+i*sin((11*π)/6)) | |
| 2√(,2)*(cos((3*π)/4)+i*sin((3*π)/4)) | |
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| 6,Period=2*π,Phase Shift=0 | |
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| 1,Period=2*π,Phase Shift=π/2 | |
| 2,Period=2,Phase Shift=3/π | |
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| 1,Period=2*π,Phase Shift=0 | |
| 1,Period=π,Phase Shift=−π/4 | |
| 2,Period=2*π,Phase Shift=0 | |
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(sec(x)−tan(x))2=(1−sin(x))/(1+sin(x)) | | |
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| sin(x)* is a conditional equation, not an identity. | |
csc(x)−cos(x)*cot(x)=sin(x) | | |
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sin(x+y)+sin(x−y)=2*sin(x)*cos(y) | | |
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cos(x)/sec(x)+sin(x)/csc(x) | | |
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((sin(x)+cos(x))2)/(1+2*sin(x)*cos(x)) | | |
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(1+sin(u))/cos(u)+cos(u)/(1+sin(u)) | | |
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| (7*π)/6+2*k*π,(11*π)/6+2*k*π | |
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| (7*π)/6+2*n*π,(11*π)/6+2*n*π | |
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| (4*π)/3+2*k*π,(5*π)/3+2*k*π | |
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sin(x)*cos(2*x)+cos(x)*sin(2*x)=0 | | |
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sin((7*π)/12)*cos(π/12)−cos((7*π)/12)*sin(π/12) | | |
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