Simplify cos(arcsin(8/x))
Problem
Solution
Identify the inner expression as an angle
θ=arcsin(8/x) which impliessin(θ)=8/x Relate the trigonometric functions using the Pythagorean identity
cos^2(θ)+sin^2(θ)=1 Substitute the value of
sin(θ) into the identity to getcos^2(θ)+(8/x)^2=1 Solve for
cos(θ) by subtracting the squared term from both sides:cos^2(θ)=1−64/(x^2) Simplify the expression under a common denominator:
cos^2(θ)=(x^2−64)/(x^2) Take the square root to find
cos(θ) assuming the range of the arcsine function (−π/2≤θ≤π/2 where the cosine is non-negative.
Final Answer
Want more problems? Check here!