Factor x^2-10x+25

Problem

x^2−10*x+25

Solution

1. Identify the structure of the quadratic expression, which is in the form a*x^2+b*x+c where a=1 b=−10 and c=25

2. Recognize that the expression is a perfect square trinomial because the first term is x^2 the last term is 5^2 and the middle term is −2*(x)*(5)

3. Apply the formula for a perfect square trinomial, which states a^2−2*a*b+b^2=(a−b)^2

4. Substitute a=x and b=5 into the formula to get (x−5)^2

Final Answer

x^2−10*x+25=(x−5)^2

Want more problems? Check here!