Graph y=x^2+1
Problem
Solution
Identify the type of function. This is a quadratic function in the form
y=a*x2+c which represents a parabola.Determine the vertex. Since there is no
x term (b=0 , thex coordinate of the vertex is0 Substitutingx=0 into the equation givesy=0+1=1 The vertex is(0,1) Determine the direction of opening. Since the coefficient of
x2 isa=1 which is positive, the parabola opens upward.Calculate additional points to define the shape. For
x=1 y=1+1=2 Forx=−1 y=(−1)2+1=2 Forx=2 y=2+1=5 Forx=−2 y=(−2)2+1=5 Plot the vertex
(0,1) and the points(1,2) (−1,2) (2,5) and(−2,5) on a coordinate plane and draw a smooth curve through them.
Final Answer
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