Find the Vertex f(x)=x^2

Problem

ƒ(x)=x2

Solution

1. Identify the coefficients of the quadratic function in the standard form ƒ(x)=a*x2+b*x+c

2. Determine the values for a b and c from the given function ƒ(x)=x2

a=1

b=0

c=0

3. Apply the formula for the x-coordinate of the vertex, which is x=(−b)/(2*a)

x=(−0)/(2*(1))

x=0

4. Substitute the x-coordinate back into the original function to find the y-coordinate.

ƒ(0)=(0)2

ƒ(0)=0

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(0,0)

Want more problems? Check here!