Evaluate the Limit
Problem
Solution
Identify the type of limit by substituting the value
x=−1 into the expression.Substitute the value into the numerator:
(−1)^2−8*(−1)=1+8=9 Substitute the value into the denominator:
(−1)^2−7*(−1)−8=1+7−8=0 Analyze the result of the substitution, which is
9/0 Since the numerator is a non-zero constant and the denominator approaches zero, the limit does not exist as a finite number and represents a vertical asymptote.Check the behavior from the left (
x→−1^− . The numerator is positive (9 . In the denominator,x^2−7*x−8=(x−8)*(x+1) Asx→−1^− (x−8)→−9 and(x+1) is a small negative number. Their product is a small positive number. Thus,9/0^+→∞ Check the behavior from the right (
x→−1^+ . The numerator is positive (9 . In the denominator,(x−8)→−9 and(x+1) is a small positive number. Their product is a small negative number. Thus,9/0^−→−∞ Conclude that because the one-sided limits do not match, the two-sided limit does not exist.
Final Answer
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