5.1 DE Basics and Exact ODEs

DE Basics


Linear Nth Order ODE:

dn(y)d(x)n+p1⁡(x)⁢dn-1(y)d(x)n-1+⋯+pn-1⁡(x)⁢d(y)d(x)+pn⁡(x)⁢y⁡(x)=g⁡(x) the fraction with numerator the n-th power of d of y and denominator d of x to the n-th power plus p sub 1 of x the fraction with numerator the n minus 1 power of d of y and denominator d of x raised to the n minus 1 power plus dot dot dot plus p sub n minus 1 of x d of y over d of x plus p sub n of x y of x equals g of x

If g⁡(x)=0 g of x equals 0 then it is homogeneous.

If g⁡(x)≠0 g of x is not equal to 0 then it is non-homogeneous.

ygen⁢(x)=yhom⁢(x)+ypar⁢(x) y sub gen times x equals y sub hom times x plus y sub par times x

If the Wronskian is zero then the solutions aren't linearly independent:

W⁡(y1,⋯,yn)=|y1y2⋯yny1′y2′⋯yn′y1n-1y2n-1⋯ynn-1| W of open paren y sub 1 comma dot dot dot comma y sub n close paren equals the determinant of the 4 by 4 matrix Row 1: Column 1, y sub 1 Column 2, y sub 2 Column 3, dot dot dot Column 4, y sub n Row 2: Column 1, y sub 1 prime Column 2, y sub 2 prime Column 3, dot dot dot Column 4, y sub n prime Row 3: Column 1, blank Column 2, blank Column 3, blank Column 4, blank Row 4: Column 1, y sub 1 raised to the n minus 1 power Column 2, y sub 2 raised to the n minus 1 power Column 3, dot dot dot Column 4, y sub n raised to the n minus 1 power

If k=λ+i⁢μ k equals lamda plus i mu then:

yhom=eλ⁢x⁢(c1⁢cos⁡(μ)⁢x+c2⁢sin⁡(μ)⁢x) y sub hom equals e raised to the lamda x power times open paren c sub 1 cosine mu x plus c sub 2 sine mu x close paren

The Chain Rule:

∂(u)∂(t)=∂(u)∂(x)⁢∂(x)∂(t)+∂(u)∂(y)⁢∂(y)∂(t) the fraction with numerator partial differential u and denominator partial differential t equals the fraction with numerator partial differential u and denominator partial differential x the fraction with numerator partial differential x and denominator partial differential t plus the fraction with numerator partial differential u and denominator partial differential y the fraction with numerator partial differential y and denominator partial differential t

Exact ODEs


M⁡(x,y)+N⁡(x,y)⁢d(y)d(x)=0 M of open paren x comma y close paren plus N of open paren x comma y close paren d of y over d of x equals 0

⇔ left right double arrow

ψx=∂(M)∂(y)=∂(N)∂(x)=ψx psi sub x equals the fraction with numerator partial differential M and denominator partial differential y equals the fraction with numerator partial differential N and denominator partial differential x equals psi sub x

ODE Methods & Laplace Transforms -> click


D'Alembert: y⁡(x)= y of x equalsold solution×u⁡(x) times u of x.

Variation of parameters: ypar=∑j=1n(uj⁡(x)⁢yj⁡(x)) y sub par equals the sum from j equals 1 to n of open paren u sub j of x y sub j of x close paren

Diagonalization: x=T⁢y x equals T y:

T⁢y′=A⁢T⁢y+g⁡(t)⇒d(y)d(t)=D⁢y+T-1⁢g=D⁢y+h T y prime equals A T y plus g of t right double arrow d of y over d of t equals D y plus T to the negative 1 power g equals D y plus h

Systems, Stability, Fourier, PDEs -> click


First solution:

x(1)=eλ⁢t⁢ξλ x raised to the 1 power equals e raised to the lamda t power xi sub lamda

Second solution:

x(2)=t⁢ℇλ⁢t⁢ξ+ℇλ⁢t⁢η x raised to the 2 power equals t ℇ raised to the lamda t power xi plus ℇ raised to the lamda t power eta

where ξ=(A-λ⁢𝕀)⁢η xi equals open paren A minus lamda double struck I close paren times eta. Third solution:

x(3)=t22⁢eλ⁢t⁢ξλ+t⁢ℇλ⁢t⁢η+eλ⁢t⁢ζ x raised to the 3 power equals the fraction with numerator t squared and denominator 2 e raised to the lamda t power xi sub lamda plus t ℇ raised to the lamda t power eta plus e raised to the lamda t power zeta

where η=(A-λ⁢𝕀)⁢ζ eta equals open paren A minus lamda double struck I close paren times zeta.


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