Factor 2x^2-x-10

Problem

2*x2−x−10

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=2 b=−1 and c=−10

2. Find two numbers that multiply to a⋅c=2⋅(−10)=−20 and add to b=−1

3. Determine the pair of numbers, which are −5 and 4 since (−5)⋅4=−20 and −5+4=−1

4. Rewrite the middle term −x using these two numbers as −5*x+4*x

2*x2−5*x+4*x−10

5. Factor by grouping by taking the greatest common factor out of the first two terms and the last two terms.

x*(2*x−5)+2*(2*x−5)

6. Factor out the common binomial factor (2*x−5)

(x+2)*(2*x−5)

Final Answer

2*x2−x−10=(x+2)*(2*x−5)

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