Find the Center and Radius (x-4)^2+y^2=16

Problem

(x−4)^2+y^2=16

Solution

1. Identify the standard form of a circle equation, which is (x−h)^2+(y−k)^2=r^2 where (h,k) represents the center and r represents the radius.

2. Rewrite the given equation (x−4)^2+y^2=16 to match the standard form more closely by expressing y^2 as (y−0)^2

3. Compare the terms to find the coordinates of the center.

h=4

k=0

4. Determine the radius by setting r^2 equal to the constant on the right side of the equation.

r^2=16

r=√(,16)

r=4

Final Answer

Center: *(4,0), Radius: *4

Want more problems? Check here!