Find the Vertex x^2=4y

Problem

x^2=4*y

Solution

1. Identify the form of the parabola. The equation is in the standard form x^2=4*p*y where the squared term is x

2. Determine the vertex from the standard form (x−h)^2=4*p*(y−k) where the vertex is located at the point (h,k)

3. Compare the given equation x^2=4*y to the standard form (x−0)^2=4*(1)*(y−0)

4. Extract the values for h and k which are h=0 and k=0

Final Answer

Vertex=(0,0)

Want more problems? Check here!