Evaluate natural log of 5- square root of 6
Problem
Solution
Identify the expression as the natural logarithm of the difference between
5 and the square root of6 Calculate the value of the square root of
6 which is approximately2.4494897 Subtract this value from
5 to find the argument of the logarithm:$5 - 2.4494897 = 2.5505103$.Apply the natural logarithm function to the result:
ln(2.5505103)≈0.9363
Final Answer
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